NCERT Solutions for Class 5 Mathematics Math Mela Chapter 9

NCERT solutions for Class 5 Mathematics Chapter Coconut Farm – complete answers & explanations

This blog provides NCERT solutions for Class 5 Mathematics Chapter Coconut Farm from Maths Mela. This chapter focuses on division, patterns, and real-life problem solving using numbers. It helps students understand how division works in daily situations like farming, money, and grouping. These NCERT solutions are strictly based on the worksheet provided and follow the exact order of questions to help students learn and practice effectively.

What this NCERT chapter covers?

1. Understanding division and its relationship with multiplication
2. Solving real-life problems using division
3. Patterns in division and place value
4. Working with large numbers and remainders
5. Mathematical reasoning and statements
6. Application of division in practical situations like farms and markets

How to use these NCERT solutions?

1. First, try solving all questions from the worksheet on your own
2. Use these NCERT solutions to check your answers step-by-step
3. Carefully compare your method with the given answers
4. Parents and teachers can guide students by discussing mistakes
5. Follow the same order of questions as given in the worksheet

Important tips & tricks for students

1. Always check multiplication to verify division answers
2. Pay attention to place values while dividing large numbers
3. Practice solving word problems carefully
4. Do not ignore remainders in division
5. Read each question properly before solving

NCERT solutions – complete answer key

Think and answer

4 × 8 = 32
32 ÷ 4 = 8
32 ÷ 8 = 4

Let Us Play

72
60
48
36
24
40

54
42
56

Let Us Do

30 × 30 = 900
900 ÷ 30 = 30
900 ÷ 30 = 30

15 × 60 = 900
900 ÷ 60 = 15
900 ÷ 15 = 60

400 × 8 = 3200
3200 ÷ 8 = 400
3200 ÷ 400 = 8

200 × 16 = 3200
3200 ÷ 16 = 200
3200 ÷ 200 = 16

150 ÷ 3 = 50
100 ÷ 10 = 10
200 ÷ 20 = 10
80 ÷ 4 = 20
300 ÷ 100 = 3
440 ÷ 44 = 10
500 ÷ 5 = 100
500 ÷ 50 = 10
630 ÷ 63 = 10

Patterns in division and place values

1000 ÷ 10 = 100
1000 ÷ 100 = 10
2000 ÷ 20 = 100
3300 ÷ 300 = 11
1600 ÷ 4 = 400
3700 ÷ 37 = 100
4000 ÷ 40 = 100
2000 ÷ 2 = 1000
3300 ÷ 3 = 1100

40 ÷ 10 = 4
400 ÷ 10 = 40
4000 ÷ 10 = 400
700 ÷ 70 = 10
1400 ÷ 100 = 14
220 ÷ 20 = 11
2200 ÷ 20 = 110

110 ÷ 11 = 10
860 ÷ 86 = 10
7500 ÷ 750 = 10
8800 ÷ 88 = 100
2400 ÷ 24 = 100
440 ÷ 22 = 20

Let Us Do

1 she cycles 8 km each day
2 Seema needs to carry 42 notes of ₹ 100
3 ₹1100 is Less, Therefore, the required amount is ₹ 11000
4 There are two possible Solutions.

i)
1 + 5 = 6

ii)
1 + 7 = 8

5
(a) 1800 ÷ 18 = 100
(b) 6100 ÷ 10 = 610
(c) 7200 ÷ 100 = 72
(d) 1000 ÷ 100 = 10
(e) 870 ÷ 10 = 87
(f) 7000 ÷ 100 = 70
(g) 200 ÷ 100 = 2
(h) 130 ÷ 10 = 13

Try it!

1 64 ÷ 4 = 16
2 265 ÷ 5 = 53
3 1560 ÷ 8 = 195
4 4824 ÷ 24 = 201
5 168 ÷ 8 = 21
6 144 ÷ 4 = 36

Let Us Solve

a 64
b 109
c 21
d 202
e 64
f 201
g 31
h 199

Let Us Learn to Divide

4 × 181 = 724
So, the correct answer is No.
726 = 4 × 181 + 2

16 × 56 = 896
So, the correct answer is No.
902 = 16 × 56 + 6

Let Us Solve

1 Rani should buy samosas in pack of 6
2 9 buses needs to be arranged
3
₹50 × 10 and ₹20 × 1
₹50 × 8 and ₹20 × 6
₹50 × 6 and ₹20 × 11
₹50 × 4 and ₹20 × 16
₹50 × 2 and ₹20 × 21
₹50 × 0 and ₹20 × 26

4 each person needs to pay ₹ 139

5
(a) 295, R = 2
(b) 35, R = 3
(c) 149
(d) 29, R = 13
(e) 12, R = 38
(f) 13, R = 17

Kalpavruksha coconut oil

1 they will earn ₹ 95725
2 431 kg
3 Ibrahim sold 254 tender coconuts

Let Us Divide

a 1172
b 601
c 205
d 306

Let Us Solve

1
(a) 11 shows are needed to seat all the people who bought tickets
(b) 6 days are needed to accommodate all the people

2 each of her friend ate 200 g of ice cream

3 each person can have 5 biscuits each day

4
(a) 1809
(b) 258, R = 2
(c) 357, R = 5
(d) 593, R = 5
(e) 308, R = 20
(f) 312, R = 18

A.
(a) 340 ÷ 34 = 10
(b) 340 ÷ 17 = 20
(c) 680 ÷ 17 = 40
(d) 680 ÷ 34 = 20
(e) 170 ÷ 17 = 10
(f) 680 ÷ 68 = 10

B.
(a) 192 ÷ 4 = 48
(b) 192 ÷ 8 = 24
(c) 384 ÷ 8 = 48
(d) 384 ÷ 4 = 96
(e) 384 ÷ 8 = 48
(f) 86 ÷ 2 = 43

C.
(a) 352 ÷ 11 = 32
(b) 704 ÷ 22 = 32
(c) 704 ÷ 11 = 64
(d) 352 ÷ 22 = 16
(e) 1,408 ÷ 44 = 32

6
(a) The distance they should cycle every day = 576 ÷ 12 = 48 km
(b) The distance they should cycle each day to reach Goa in 4 days = 232 ÷ 4 = 58 km

7
(a) Missing information: The cost of each mango.
Let each mango costs ₹ 10
The cost of each basket = 12 × 10 = ₹ 120
Therefore, the cost of 6 baskets = 6 × 120 = ₹ 720
Thus, the vendor earn ₹ 720 in total

(b) Missing information: Total number of desks in the school.
Let the total number of desks in the school is 160.
Therefore, the total number of desks in each classroom = 160 ÷ 8 = 20

(d) Missing information: The cost of one idli.
Let the cost of each idli is ₹25
The cost of one plate idli = 6250 ÷ 125 = ₹ 50
Therefore, the number of idlis in one plate = 50 ÷ 25 = 2

8
the long wooden panels are sufficient for 66 bookshelves
the short wooden panels are sufficient 38 bookshelves
the small clips are sufficient for 150 bookshelves
So, large clips are sufficient for 30 bookshelves 2800 ÷ 32 = 87 and remainder 16.
So, screws are sufficient for 87 bookshelves. Based on the above data the carpenter can make 30 bookshelves

Vegetable market

Radish ₹26 78 ₹2028
Potato ₹20 112 ₹2240
Cabbage ₹32 56 ₹1792
Green Peas ₹25 125 ₹3125
Total money earned through the sale ₹9185

Let Us Solve

1
N = 506, D = 5, Q = 101, R = 1
5 × 101 + 1 = 505 + 1 = 506
Therefore, N = D × Q + R

2
N = 918, D = 8, Q = 114, R = 6
8 × 114 + 6 = 912 + 6 = 918
Therefore, N = D × Q + R

3
N = 8126, D = 7, Q = 1160, R = 6
7 × 1160 + 6 = 8120 + 6 = 8126
Therefore, N = D × Q + R

4
N = 9324, D = 4, Q = 233, R = 0
Therefore, N = D × Q + R

5
N = 876, D = 6, Q = 146, R = 0
Therefore, N = D × Q + R

6
N = 9324, D = 4, Q = 233, R = 0
Therefore, N = D × Q + R

7
N = 934, D = 12, Q = 77, R = 10
12 × 77 + 10 = 924 + 10 = 934
Therefore, N = D × Q + R

8
N = 829, D = 23, Q = 36, R = 1
23 × 36 + 1 = 828 + 1 = 829
Therefore, N = D × Q + R

9
N = 705, D = 18, Q = 39, R = 3
18 × 39 + 3 = 702 + 3 = 705
Therefore, N = D × Q + R

10
N = 705, D = 18, Q = 39, R = 3
Therefore, N = D × Q + R

11
N = 6790, D = 45, Q = 150, R = 40
45 × 150 + 40 = 6750 + 40 = 6790
Therefore, N = D × Q + R

12
N = 5074, D = 21, Q = 241, R = 13
21 × 241 + 13 = 5074
Therefore, N = D × Q + R

Mathematical statements

1
(a) True
(b) False
(c) True
(d) False
(e) True

2
(a) 7 × 6 = 25 + 17
(b) 87 + 6 = 3 × 31
(c) 63 + 7 = 74 – 4
(d) 72 ÷ 9 = 16 ÷ 2

3
(a)
1 + 3 = 4
5 + 7 = 12
9 + 11 = 20
13 + 15 = 28
17 + 19 = 36

(b) Multiplying by 2 gives odd number → Not possible

4
Answers may vary.

Why NCERT solutions help students?

NCERT solutions help students prepare effectively for exams by providing accurate answers based on the official curriculum. They improve concept clarity, especially in topics like division and patterns. Following NCERT-based answers also builds confidence and helps students understand how to present answers correctly.

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