NCERT Solutions for Class 3 Mathematics Chapter Raksha Bandhan

This worksheet is designed for Class 3 students studying Mathematics and is based on the NCERT chapter Raksha Bandhan from the Maths Mela (English) textbook. This chapter helps students understand multiplication, division, repeated addition, grouping, sharing, skip counting, and multiplication tables through fun festival-based and real-life activities. It plays an important role in building strong number sense and problem-solving skills in an engaging and practical way. This worksheet provides complete and accurate NCERT Solutions that strictly follow the chapter content and NCERT learning approach, making it useful for students, parents, and teachers.

Chapter summary: stories, poems & themes

The chapter is activity-based and uses real-life situations related to Raksha Bandhan, sweets, jalebis, spiders, shells, farms, and games to teach mathematical concepts. Students learn multiplication and division through grouping, repeated addition, equal sharing, skip jumping, and pattern observation. The chapter also includes picture observation activities and practical thinking-based exercises that help children connect maths with daily life. The main learning focus of the chapter is understanding multiplication and division in a visual and enjoyable manner.

What this NCERT chapter covers?

• Repeated addition and multiplication  
• Equal sharing and division  
• Counting objects through grouping  
• Understanding multiplication tables  
• Skip counting and skip jumping  
• Identifying number patterns  
• Picture-based observation and counting  
• Solving real-life mathematical problems  
• Understanding equal groups  
• Learning multiplication facts using activities and games  

How to use these NCERT solutions?

Students should first attempt all activities and questions on their own before checking the answers. Parents and teachers can use these NCERT Solutions to guide children in understanding multiplication, division, grouping, and sharing methods step by step. The solutions follow the exact NCERT order and structure, which helps students revise concepts correctly and improve confidence in solving maths problems independently.

Student tips & learning tricks

Students should practice multiplication tables regularly to solve questions faster. While solving repeated addition problems, they should carefully count equal groups. During division activities, students should distribute items equally and check if anything is left over. Skip counting and jump activities should be practiced slowly and carefully to avoid counting mistakes. Drawing groups and objects can help students understand multiplication and division better as per NCERT expectations.

Why NCERT solutions are important?

NCERT Solutions help students learn concepts exactly according to the school syllabus. They build strong foundational maths skills through simple explanations and activity-based learning. Using NCERT-aligned solutions improves understanding of multiplication, division, patterns, and equal grouping. These solutions also increase confidence and help students prepare well for classroom learning and assessments.

Complete answer key – NCERT solutions

Picture Observation

1. Interesting things observed in the house:  
Decorated house with flowers and leaves, baskets of fruits, glasses arranged on the table, and family members preparing for Raksha Bandhan.

2. Count and write:  
1. Leaves – 24  
2. Glasses – 30  
3. Pomegranate – 24  
4. Flowers – 20  

Let’s make Rakhis

For each Rakhi we need:  
1 flower  
2 threads  
4 beads  

We need to make 5 Rakhis.  

1 + 1 + 1 + 1 + 1 = 5  
We need 5 flowers.  

2 + 2 + 2 + 2 + 2 = 10  
We need 10 threads.  

4 + 4 + 4 + 4 + 4 = 20  
We need 20 beads.  

Try it Out

1. For making 10 such Rakhis:  
Flowers = 10  
Threads = 20  
Beads = 40  

2. If there are 30 flowers, 30 threads, and 30 beads:  
Each Rakhi needs:  
1 flower, 2 threads, 4 beads  

Maximum Rakhis possible = 7  

Explanation: To visually understand, you can draw the materials and distribute them into the number of Rakhis.

Jagannath Sweet Shop

1.  
3 + 3 + 3 = 9  
3 × 3 = 9  
There are 9 laddoos in the box.

2.  
Two boxes of laddoos  
2 × 9 = 18  
There are 18 laddoos.

3. Repeated addition  
3 + 3 + 3 + 3 + 3 + 3 = 18  
6 × 3 = 18  
There are 18 laddoos.

Can you help Dhara find this out?

Dhara has 18 laddoos and 9 friends. She wants to give the laddoos equally to everyone.

So, she puts 1 laddoo on each plate first. Since there are 9 plates, she uses 9 laddoos.

Items left:  
18 - 9 = 9 laddoos left

Then she puts 1 more laddoo on each plate. Again, she uses 9 laddoos.

Items left:  
9 - 9 = 0 laddoos left

Now every plate has 2 laddoos.

So, when 18 laddoos are shared equally among 9 friends, each friend gets 2 laddoos.

Answer:  
18 ÷ 9 = 2

Try it Out

Total number of kaju katlis = 20  

Items left 20 - 5 = 15

Let us Do

1. Distribute 16 kaju katlis among 4 people.

Explanation:  
Start with 16 kaju katlis. Share them equally among 4 people by giving one to each person repeatedly. Continue until all are distributed. Each person will get 4 kaju katlis.

16 - 4 = 12 items left  
12 - 4 = 8 items left  
8 - 4 = 4 items left  
4 - 4 = 0 items left  

Each gets 4 kaju katlis.  

16 ÷ 4 = 4

2. Distribute 15 pedas among 5 people.

Explanation:  
Start with 15 pedas. Distribute them equally among 5 people by giving one peda to each person again and again until all are shared. Each person will get 3 pedas.

15 - 5 = 10 - 5 = 5 - 5 = 0

15 equally shared by 5 is 3 each  

15 ÷ 5 = 3

Let us Think

1.  
12 equally divided by 2 is 6.  

12 ÷ 2 = 6  

6 cycles can be fitted with 12 wheels.

2. Look at the picture carefully. Count the number of jalebis.

There are 24 jalebis.

Explanation: you can count by grouping them. (answers may vary)

4 + 4 + 4 + 4 + 4 + 4 = 24  
6 × 4 = 24

Dhara’s family has 9 members.  
To give 4 each:  

9 × 4 = 36

No, there are not enough jalebis.  
Dhara should buy 12 more jalebis.

Plants in the Garden

1.  
6 + 6 + 6 + 6 + 6 + 6 + 6 + 6 = 48  

8 × 6 = 48  
6 × 8 = 48

Both Dhara and Gopal are correct.

Different ways of grouping

1. Yes, the given grouping can be written as multiplication.

For example:  
8 groups of 6 = 8 × 6 = 48

Yes, more equal groupings can be:  
6 groups of 8 = 6 × 8 = 48  
4 groups of 12 = 4 × 12 = 48

Visit to a Farm (Chickens)

1.  
4 times 2 is 8  
5 times 2 is 10  
6 times 2 is 12  
7 times 2 is 14  
8 times 2 is 16  
9 times 2 is 18  
10 times 2 is 20

4 × 2 = 8  
5 × 2 = 10  
6 × 2 = 12  
7 × 2 = 14  
8 × 2 = 16  
9 × 2 = 18  
10 × 2 = 20

Skip Jumping Game

1.  
4 jumps → 3 + 3 + 3 + 3 = 12 = 4 × 3  
5 jumps → 3 + 3 + 3 + 3 + 3 = 15 = 5 × 3  
6 jumps → 3 + 3 + 3 + 3 + 3 + 3 = 18 = 6 × 3  
7 jumps → 3 + 3 + 3 + 3 + 3 + 3 + 3 = 21 = 7 × 3  
8 jumps → 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = 24 = 8 × 3  
9 jumps → 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = 27 = 9 × 3  
10 jumps → 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = 30 = 10 × 3

Let us Do

1. 12  

2. Yes  

3. 3  

4. 6, 12, 18, 24, 30, 36, 42, 48  

5.  
6 × 1 = 6  
6 × 2 = 12  
6 × 3 = 18  
6 × 4 = 24  
6 × 5 = 30  
6 × 6 = 36  
6 × 7 = 42  
6 × 8 = 48  
6 × 9 = 54  
6 × 10 = 60

6. Explanation:  
Yes, repeated addition is happening. Add 4 again and again to form the times-4 table. For example, 4 + 4 = 8, 4 + 4 + 4 = 12, and so on.

7.  
9 (steps)  
36

8. Explanation:  
Gopal makes 9 equal jumps. So, the times table formed is the table of 9.

9 × 1 = 9  
9 × 2 = 18  
9 × 3 = 27  
9 × 4 = 36  
9 × 5 = 45  
9 × 6 = 54  
9 × 7 = 63  
9 × 8 = 72  
9 × 9 = 81  
9 × 10 = 90

9. Explanation:  
Gopal makes 9 equal jumps. So, the times table formed is the table of 9.

9 × 1 = 9  
9 × 2 = 18  
9 × 3 = 27  
9 × 4 = 36  
9 × 5 = 45  
9 × 6 = 54  
9 × 7 = 63  
9 × 8 = 72  
9 × 9 = 81  
9 × 10 = 90

Let us Play

1. 6

Explanation:  
Choosing 6 helps reach 12 in the minimum number of jumps.  
0 → 6 → 12 (only 2 jumps), which is fewer than using 3 or smaller steps.

2. Explanation:  
Place the flower on different numbers on the track. Try different skip numbers (like 2, 3, 4, 6, etc.) and count the number of jumps needed. Compare with your friends and see who reaches the number in the least jumps.

3. 1, 2, 3

Explanation:  
These numbers can be reached only by skip jumping of 1 because no larger equal jumps (like 2, 3, etc.) can land exactly on them starting from 0.

Fun Way of Writing Tables

1. Explanation:  
Draw sticks in two directions to form rows and columns. The points where the sticks intersect (red dots) show the total. Count these dots to get the product. This shows repeated addition in a visual way.

1 × 5 = 5  
2 × 5 = 10  
3 × 5 = 15  
4 × 5 = 20  
5 × 5 = 25  
6 × 5 = 30  
7 × 5 = 35  
8 × 5 = 40  
9 × 5 = 45

Explanation:  
Use the same sticks method to make tables from 6 to 10. Draw equal groups using sticks and count the intersection points each time to find the answers for times-6, times-7, times-8, times-9, and times-10 tables.

Seeing Patterns in Multiplication Tables

1. Numbers in the 5 times table end with 0 or 5.

2.  
11 × 5 → 5  
12 × 5 → 0

3.  
(i) 2, 4, 6  
(ii) 1, 3, 7

Last digit of 18 × 5 will be 0  
Last digit of 23 × 5 will be 5  
Last digit of 32 × 5 will be 0  
Last digit of 50 × 5 will be 0

Look at the times tables of 2, 3, 5. They have a relation between them. Can you see it?

Explanation:  
Yes, the numbers in the 2 times table and 3 times table add up to give the numbers in the 5 times table.

2 + 3 = 5  
4 + 6 = 10  
6 + 9 = 15  
8 + 12 = 20

Can you find other examples of two tables adding up to a third table?

Explanation:  
Yes, other examples are:  
3 and 4 tables → 7 table  
2 and 4 tables → 6 table  
5 and 3 tables → 8 table

Let us Do

1.  
a. 20 cookies  
b. 24 idlis  
c. 6 cookies each  
d. Jump size = 3  
e. Example: 2 + 4 + 3 + 3 + 3 + 3 = 18  
f. 7 days  
g. 28 sea shells left

2. Solve

a. 4 × 9 = 36  
b. 32 ÷ 8 = 4  
c. 6 × 7 = 42  
d. 45 ÷ 5 = 9

Help Bhim

Each wheel needs 5 spokes.

10 wheels will need = 50 spokes

Another 10 wheels → 10 × 5 = 50 spokes

Total spokes = 50 + 50 = 100 spokes

Try these

First 10 wheels will have 50 spokes  
Next 10 wheels will have 50 spokes  
Next 10 wheels will have 50 spokes  

Total = 150 spokes  

30 × 5 = 150 spokes

Complete the following

40 × 5 = 200  
50 × 5 = 250  
60 × 5 = 300  
70 × 5 = 350  
80 × 5 = 400  
90 × 5 = 450  
100 × 5 = 500

1. 9 (wheels)

Explanation:  
Each wheel needs 5 spokes.  

45 ÷ 5 = 9 wheels.

2. No

Explanation:  
10 wheels need 10 × 5 = 50 spokes, but Dhara has only 45 spokes.

3. 12 (wheels)

Explanation:  
60 ÷ 5 = 12 wheels.

Let us Do (Spiders)

1.  
A spider has 8 legs.  

5 spiders → 40 legs  
10 spiders → 80 legs  
15 spiders → 120 legs

2. 23 spiders → 184 legs

3. 32 legs → 4 spiders

4.  
a. 18 auto rickshaws → 54 wheels  
b. 34 auto rickshaws → 102 wheels

5. 36 wheels → 12 auto rickshaws

6. 55 ants → 330 legs

7. 48 cow legs → 12 cows

8. 24 horns → 12 cows → 48 legs

Let us Think

1. Largest number before crossing 50 → 49

2. Number after which jump not possible → 50

3. Starting numbers → 0, 7, 14, 21, 28, 35, 42, 49

Puri Beach

1. Two wall hangings cost

2 × 42 = 84

2.  
Notes given = 4  
Money returned = 25  
Total cost = 375

Sea Shells

1. 56  

2. 28  

3. Yes  

4. 4

Try These

1. 100 ÷ 17 = 5 necklaces

2. 127 ÷ 3 = 42 each

3.  
(i) 50 rupees notes → 10  
(ii) 20 rupees notes → 25  
(iii) 10 rupees notes → 50

Let us Explore

1. Cards inside envelopes

7 → 1 and 7  
18 → 3 and 6  
32 → 4 and 8  
20 → 4 and 5  
45 → 5 and 9

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