NCERT Solutions for Class 3 Mathematics Maths Mela (English) Chapter 7

NCERT Solutions for Class 3 Mathematics Maths Mela (English) Chapter 7
Last Updated At: 20 May 2026
13 min read

NCERT solutions for Grade 3 Mathematics Chapter 7 Raksha Bandhan – complete answers & explanations

This blog provides complete NCERT solutions for Grade 3 Mathematics Chapter 7 Raksha Bandhan from the Maths Mela (English) textbook. This chapter introduces students to important maths concepts through fun activities connected to the festival of Raksha Bandhan. Children learn repeated addition, multiplication, division, equal grouping, skip counting, sharing, and number patterns in a simple and engaging way. The chapter uses real-life examples such as laddoos, rakhis, flowers, beads, jalebis, and sea shells to help students understand mathematical operations easily. These NCERT solutions support students in building strong problem-solving skills and understanding multiplication and division in practical situations. Parents and teachers can also use these answers to guide children step-by-step during practice and revision.

 Download the worksheet and practice alongside solutions for better clarity and stronger learning. The answers are written in a simple and organised format to help students revise concepts confidently and prepare well for exams. Book a free trial now to get expert guidance and improve maths skills through interactive learning support.

NCERT Solutions for Class 3 Mathematics Maths Mela (English) Chapter 7.png

What this NCERT chapter covers?

1. The chapter introduces multiplication through repeated addition using simple real-life examples.
2. Students learn equal grouping and sharing through sweets, flowers, beads, and festival activities.
3. The chapter explains division as equal distribution among people and groups.
4. Children practice skip counting and multiplication tables in an interactive way.
5. The chapter helps students understand patterns in multiplication tables.
6. Students learn how multiplication and division are connected to daily activities.
7. The chapter develops counting and observation skills through picture-based activities.
8. Learners practice solving word problems using multiplication and division.
9. The chapter encourages logical thinking through grouping and sharing exercises.
10. Students explore different ways of arranging equal groups and understanding products.
11. The chapter also improves mental maths skills using repeated addition and skip jumping games.
12. Overall, the chapter builds confidence in multiplication, division, and practical problem-solving.

How to use these NCERT solutions?

1. Start by reading each question carefully before looking at the answers.
2. Try solving the problems on your own using repeated addition, grouping, or division methods.
3. Use the solutions to check whether your answers and steps are correct.
4. Compare your method with the given explanation to understand the correct approach.
5. Practice multiplication tables regularly while solving chapter questions.
6. Parents and teachers can guide students by explaining grouping and sharing activities with real objects.
7. Follow the same order of questions given in the worksheet for easy learning and revision.
8. Revise the explanations carefully to improve concept clarity in multiplication and division.
9. Use picture-based activities to strengthen observation and counting skills.
10. Practice similar examples again to improve speed and accuracy in maths calculations.

Important tips & tricks for students

1. Always count carefully while doing grouping and sharing activities.
2. Use repeated addition to understand multiplication easily.
3. Learn multiplication tables regularly for faster calculations.
4. Read word problems slowly and identify the numbers correctly.
5. Practice skip counting to improve multiplication skills.
6. Check whether items are shared equally while solving division questions.
7. Use drawings or objects when concepts feel difficult to understand.
8. Revise number patterns in multiplication tables carefully.
9. Avoid rushing while counting objects in picture-based questions.
10. Practice daily to build confidence in multiplication and division.

NCERT solutions – complete answer key

Picture Observation

1. Interesting things observed in the house:  
Decorated house with flowers and leaves, baskets of fruits, glasses arranged on the table, and family members preparing for Raksha Bandhan.

Let’s make Rakhis

For each Rakhi we need:  
1 flower  
2 threads  
4 beads

We need to make 5 Rakhis.

1+1+1+1+1=5  
We need 5 flowers.

2+2+2+2+2=10  
We need 10 threads.

4+4+4+4+4=20  
We need 20 beads.

2. Count and write:  
Leaves – 24  
Glasses – 30  
Pomegranate – 24  
Flowers – 20

Try it Out

1. For making 10 such Rakhis:  
Flowers = 10  
Threads = 20  
Beads = 40

2. If there are 30 flowers, 30 threads, and 30 beads:  
Each Rakhi needs:  
1 flower, 2 threads, 4 beads

Maximum Rakhis possible = 7

Explanation : To visually understand, you can draw the materials and distribute them into the number of Rakhis.

Jagannath Sweet Shop

1.  
3 + 3 + 3 = 9  
3 × 3 = 9  
There are 9 laddoos in the box.

2.  
Two boxes of laddoos

2 × 9 = 18  
There are 18 laddoos.

3. Repeated addition

3 + 3 + 3 + 3 + 3 + 3 = 18  
6 × 3 = 18  
There are 18 laddoos.

Can you help Dhara find this out?

Dhara has 18 laddoos and 9 friends. She wants to give the laddoos equally to everyone.

So, she puts 1 laddoo on each plate first. Since there are 9 plates, she uses 9 laddoos.

Items left:  
18 - 9 = 9 laddoos left

Then she puts 1 more laddoo on each plate. Again, she uses 9 laddoos.

Items left:  
9 - 9 = 0 laddoos left

Now every plate has 2 laddoos.

So, when 18 laddoos are shared equally among 9 friends, each friend gets 2 laddoos.

Answer:  
18 ÷ 9 = 2

Try it Out

Total number of kaju katlis = 20

Items left 20-5 =15

Let us Do

1. Distribute 16 kaju katlis among 4 people.

Explanation:  
Start with 16 kaju katlis. Share them equally among 4 people by giving one to each person repeatedly. Continue until all are distributed. Each person will get 4 kaju katlis.

16-4 =12 items left  
12-4 = 8 items left  
8-4 = 4 items left  
4-4 = 0 items left

Each gets 4 kaju katlis.

16 ÷ 4 = 4

2. Distribute 15 pedas among 5 people.

Explanation:  
Start with 15 pedas. Distribute them equally among 5 people by giving one peda to each person again and again until all are shared. Each person will get 3 pedas.

15-5=10-5=5-5=0

15 equally shared by 5 is 3 each

15 ÷ 5 = 3

Let us Think

1.  
12 equally divided by 2 is 6.

12 ÷ 2 = 6

6 cycles can be fitted with 12 wheels.

2. Look at the picture carefully. Count the number of jalebis

There are 24 jalebis.

Explanation: you can count by grouping them. ( answers may Vary)

4 + 4 + 4 + 4 + 4 + 4 = 24

6 × 4 = 24

Dhara’s family has 9 members.

To give 4 each:

9 × 4 = 36

No, there are not enough jalebis.

Dhara should buy 12 more jalebis.

Plants in the Garden

1.  
6 + 6 + 6 + 6 + 6 + 6 + 6 + 6 = 48

8 × 6 = 48

6 × 8 = 48

Both Dhara and Gopal are correct.

Different ways of grouping.

1.  
Yes, the given grouping can be written as multiplication.

For example:  
8 groups of 6 = 8 × 6 = 48

Yes, more equal groupings can be:  
6 groups of 8 = 6 × 8 = 48

4 groups of 12 = 4 × 12 = 48

Visit to a Farm (Chickens)

1.  
4 times 2 is 8  
5 times 2 is 10  
6 times 2 is 12  
7 times 2 is 14  
8 times 2 is 16  
9 times 2 is 18  
10 times 2 is 20

4 × 2 = 8  
5 × 2 = 10  
6 × 2 = 12  
7 × 2 = 14  
8 × 2 = 16  
9 × 2 = 18  
10 × 2 = 20

Skip Jumping Game

1.  
4 jumps → 3 + 3 + 3 + 3 = 12 = 4 × 3

5 jumps → 3 + 3 + 3 + 3 + 3 = 15 = 5 × 3

6 jumps → 3 + 3 + 3 + 3 + 3 + 3 = 18 = 6 × 3

7 jumps → 3 + 3 + 3 + 3 + 3 + 3 + 3 = 21 = 7 × 3

8 jumps → 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = 24 = 8 × 3

9 jumps → 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = 27 = 9 × 3

10 jumps → 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 = 30 = 10 × 3

Let us Do

1. 12

2. Yes

3. 3

4. 6, 12, 18, 24, 30, 36, 42, 48

5.  
6 × 1 = 6  
6 × 2 = 12  
6 × 3 = 18  
6 × 4 = 24  
6 × 5 = 30  
6 × 6 = 36  
6 × 7 = 42  
6 × 8 = 48  
6 × 9 = 54  
6 × 10 = 60

6. Explanation:  
Yes, repeated addition is happening. Add 4 again and again to form the times-4 table. For example, 4 + 4 = 8, 4 + 4 + 4 = 12, and so on.

7.  
9 (steps)

36

8. Explanation:  
Gopal makes 9 equal jumps. So, the times table formed is the table of 9.

9 × 1 = 9  
9 × 2 = 18  
9 × 3 = 27  
9 × 4 = 36  
9 × 5 = 45  
9 × 6 = 54  
9 × 7 = 63  
9 × 8 = 72  
9 × 9 = 81  
9 × 10 = 90

9. Explanation:  
Gopal makes 9 equal jumps. So, the times table formed is the table of 9.

9 × 1 = 9  
9 × 2 = 18  
9 × 3 = 27  
9 × 4 = 36  
9 × 5 = 45  
9 × 6 = 54  
9 × 7 = 63  
9 × 8 = 72  
9 × 9 = 81  
9 × 10 = 90

Let us Play

1. 6

Explanation:  
Choosing 6 helps reach 12 in the minimum number of jumps.  
0 → 6 → 12 (only 2 jumps), which is fewer than using 3 or smaller steps.

2. Explanation:  
Place the flower on different numbers on the track. Try different skip numbers (like 2, 3, 4, 6, etc.) and count the number of jumps needed. Compare with your friends and see who reaches the number in the least jumps.

3. 1, 2, 3

Explanation:  
These numbers can be reached only by skip jumping of 1 because no larger equal jumps (like 2, 3, etc.) can land exactly on them starting from 0.

Fun Way of Writing Tables

1. Explanation:  
Draw sticks in two directions to form rows and columns. The points where the sticks intersect (red dots) show the total. Count these dots to get the product. This shows repeated addition in a visual way.

1 × 5 = 5  
2 × 5 = 10  
3 × 5 = 15  
4 × 5 = 20  
5 × 5 = 25  
6 × 5 = 30  
7 × 5 = 35  
8 × 5 = 40  
9 × 5 = 45

Explanation:  
Use the same sticks method to make tables from 6 to 10. Draw equal groups using sticks and count the intersection points each time to find the answers for times-6, times-7, times-8, times-9, and times-10 tables.

Seeing Patterns in Multiplication Tables

1. Numbers in the 5 times table end with 0 or 5.

2.  
11 × 5 → 5  
12 × 5 → 0

3.  
(i) 2, 4, 6  
(ii) 1, 3, 7

Last digit of 18 × 5 will be 0

Last digit of 23 × 5 will be 5

Last digit of 32 × 5 will be 0

Last digit of 50 × 5 will be 0

Look at the times tables of 2, 3, 5. They have a relation between them. Can you see it?

Explanation:  
Yes, the numbers in the 2 times table and 3 times table add up to give the numbers in the 5 times table.

2 + 3 = 5  
4 + 6 = 10  
6 + 9 = 15  
8 + 12 = 20

Can you find other examples of two tables adding up to a third table?

Explanation:  
Yes, other examples are:

3 and 4 tables → 7 table

2 and 4 tables → 6 table

5 and 3 tables → 8 table

Let us Do

1.  
a. 20 cookies  
b. 24 idlis  
c. 6 cookies each  
d. Jump size = 3  
e. Example: 2 + 4 + 3 + 3 + 3 + 3 = 18  
f. 7 days  
g. 28 sea shells left

2. Solve

a. 4 × 9 = 36  
b. 32 ÷ 8 = 4  
c. 6 × 7 = 42  
d. 45 ÷ 5 = 9

Help Bhim

Each wheel needs 5 spokes.

10 wheels will need = 50 spokes

Another 10 wheels → 10 × 5 = 50 spokes

Total spokes = 50+50 = 100 spokes

Try these

First 10 wheels will have 50 spokes

Next 10 wheels will have 50 spokes

Next 10 wheels will have 50 spokes

Total = 150 spokes

30 × 5 = 150 spokes

Complete the following

40 × 5 = 200  
50 × 5 = 250  
60 × 5 = 300  
70 × 5 = 350  
80 × 5 = 400  
90 × 5 = 450  
100 × 5 = 500

1. 9 (wheels)

Explanation:  
Each wheel needs 5 spokes.  
45 ÷ 5 = 9 wheels.

2. No

Explanation:  
10 wheels need 10 × 5 = 50 spokes, but Dhara has only 45 spokes.

3. 12 (wheels)

Explanation:  
60 ÷ 5 = 12 wheels.

Let us Do (Spiders)

1. A spider has 8 legs.

5 spiders → 40 legs

10 spiders → 80 legs

15 spiders → 120 legs

2. 23 spiders → 184 legs

3. 32 legs → 4 spiders

4.  
a. 18 auto rickshaws → 54 wheels  
b. 34 auto rickshaws → 102 wheels

5. 36 wheels → 12 auto rickshaws

6. 55 ants → 330 legs

7. 48 cow legs → 12 cows

8. 24 horns → 12 cows → 48 legs

Let us Think

1. Largest number before crossing 50 → 49

2. Number after which jump not possible → 50

3. Starting numbers → 0, 7, 14, 21, 28, 35, 42, 49

Puri Beach

1. Two wall hangings cost

2 × 42 = 84

2.  
Notes given = 4

Money returned = 25

Total cost = 375

Sea Shells

1. 56

2. 28

3. Yes

4. 4

Try These

1.  
100 ÷ 17 = 5 necklaces

2.  
127 ÷ 3 = 42 each

3.  
(i) 50 rupees notes → 10  
(ii) 20 rupees notes → 25  
(iii) 10 rupees notes → 50

Let us Explore

1. Cards inside envelopes

7 → 1 and 7

18 → 3 and 6

32 → 4 and 8

20 → 4 and 5

45 → 5 and 9

Why NCERT solutions help students?

NCERT solutions help students understand multiplication, division, grouping, and sharing concepts in a clear and practical way. They improve problem-solving skills, strengthen maths fundamentals, and help children practise correct NCERT-aligned methods for exams and classroom learning. These solutions also build confidence by making maths simple, engaging, and easy to revise.

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